10x+4-8x=2(x+1)

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Solution for 10x+4-8x=2(x+1) equation: 



10x+4-8x=2(x+1)

We move all terms to the left:

10x+4-8x-(2(x+1))=0

We add all the numbers together, and all the variables

2x-(2(x+1))+4=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

2x-2x-2+4=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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