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10x+4=4(3/2x+3
We move all terms to the left:
10x+4-(4(3/2x+3)=0
Domain of the equation: 2x+3)+4!=0We multiply all the terms by the denominator
x∈R
10x*2x+3)+4-(4(3=0
We add all the numbers together, and all the variables
10x*2x=0
Wy multiply elements
20x^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{40}=0$
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