10x+4=4(3/2x+3)

Solution for 10x+4=4(3/2x+3) equation:

10x+4=4(3/2x+3)

We move all terms to the left:

10x+4-(4(3/2x+3))=0


Domain of the equation: 2x+3))!=0

x∈R


We multiply all the terms by the denominator


10x*2x+4*2x+3))-(4(3+3))=0

We add all the numbers together, and all the variables

10x*2x+4*2x+3))-(46)=0

We add all the numbers together, and all the variables

10x*2x+4*2x=0

Wy multiply elements

20x^2+8x=0

a = 20; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·20·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*20}=\frac{-16}{40}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*20}=\frac{0}{40}
=0
$