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10x+5(x+8)=3-3(2-x)
We move all terms to the left:
10x+5(x+8)-(3-3(2-x))=0
We add all the numbers together, and all the variables
10x+5(x+8)-(3-3(-1x+2))=0
We multiply parentheses
10x+5x-(3-3(-1x+2))+40=0
We calculate terms in parentheses: -(3-3(-1x+2)), so:We add all the numbers together, and all the variables
3-3(-1x+2)
determiningTheFunctionDomain -3(-1x+2)+3
We multiply parentheses
3x-6+3
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
15x-(3x-3)+40=0
We get rid of parentheses
15x-3x+3+40=0
We add all the numbers together, and all the variables
12x+43=0
We move all terms containing x to the left, all other terms to the right
12x=-43
x=-43/12
x=-3+7/12
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