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10x+9(3-4x)=3-3(5x-8)-10x
We move all terms to the left:
10x+9(3-4x)-(3-3(5x-8)-10x)=0
We add all the numbers together, and all the variables
10x+9(-4x+3)-(3-3(5x-8)-10x)=0
We multiply parentheses
10x-36x-(3-3(5x-8)-10x)+27=0
We calculate terms in parentheses: -(3-3(5x-8)-10x), so:We add all the numbers together, and all the variables
3-3(5x-8)-10x
determiningTheFunctionDomain -3(5x-8)-10x+3
We add all the numbers together, and all the variables
-10x-3(5x-8)+3
We multiply parentheses
-10x-15x+24+3
We add all the numbers together, and all the variables
-25x+27
Back to the equation:
-(-25x+27)
-26x-(-25x+27)+27=0
We get rid of parentheses
-26x+25x-27+27=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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