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10x+9/2x-15=1
We move all terms to the left:
10x+9/2x-15-(1)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
10x+9/2x-16=0
We multiply all the terms by the denominator
10x*2x-16*2x+9=0
Wy multiply elements
20x^2-32x+9=0
a = 20; b = -32; c = +9;
Δ = b2-4ac
Δ = -322-4·20·9
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{19}}{2*20}=\frac{32-4\sqrt{19}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{19}}{2*20}=\frac{32+4\sqrt{19}}{40} $
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