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10x+9=3-(x-5)
We move all terms to the left:
10x+9-(3-(x-5))=0
We calculate terms in parentheses: -(3-(x-5)), so:We get rid of parentheses
3-(x-5)
determiningTheFunctionDomain -(x-5)+3
We get rid of parentheses
-x+5+3
We add all the numbers together, and all the variables
-1x+8
Back to the equation:
-(-1x+8)
10x+1x-8+9=0
We add all the numbers together, and all the variables
11x+1=0
We move all terms containing x to the left, all other terms to the right
11x=-1
x=-1/11
x=-1/11
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