10x+x2=875

Solution for 10x+x2=875 equation:

10x+x2=875

We move all terms to the left:

10x+x2-(875)=0

We add all the numbers together, and all the variables

x^2+10x-875=0

a = 1; b = 10; c = -875;
Δ = b2-4ac
Δ = 102-4·1·(-875)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-60}{2*1}=\frac{-70}{2}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+60}{2*1}=\frac{50}{2}
=25
$