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10x-(-7+6x)x=3
We move all terms to the left:
10x-(-7+6x)x-(3)=0
We add all the numbers together, and all the variables
10x-(6x-7)x-3=0
We multiply parentheses
-6x^2+10x+7x-3=0
We add all the numbers together, and all the variables
-6x^2+17x-3=0
a = -6; b = 17; c = -3;
Δ = b2-4ac
Δ = 172-4·(-6)·(-3)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{217}}{2*-6}=\frac{-17-\sqrt{217}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{217}}{2*-6}=\frac{-17+\sqrt{217}}{-12} $
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