10x-(1/3)+(5/6)=3x+(1/2)+7x

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Solution for 10x-(1/3)+(5/6)=3x+(1/2)+7x equation: 



10x-(1/3)+(5/6)=3x+(1/2)+7x

We move all terms to the left:

10x-(1/3)+(5/6)-(3x+(1/2)+7x)=0



Domain of the equation: 2)+7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

10x-(3x+(+1/2)+7x)-(+1/3)+(+5/6)=0

We get rid of parentheses

10x-(3x+(+1/2)+7x)-1/3+5/6=0

We calculate fractions


10x+(-(3x+(+1*3*6)/2+7x)*3*6)+(-12x)/2+7x)*3*6)+30x/2+7x)*3*6)=0



We calculate terms in parentheses: +(-(3x+(+1*3*6)/2+7x)*3*6), so:

-(3x+(+1*3*6)/2+7x)*3*6

We add all the numbers together, and all the variables

-(3x+18/2+7x)*3*6

We multiply all the terms by the denominator


-(3x+18

Back to the equation:

+(-(3x+18)



We can not solve this equation

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