10x-(2x-19)=-3(15-4x)

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Solution for 10x-(2x-19)=-3(15-4x) equation: 



10x-(2x-19)=-3(15-4x)

We move all terms to the left:

10x-(2x-19)-(-3(15-4x))=0

We add all the numbers together, and all the variables

10x-(2x-19)-(-3(-4x+15))=0

We get rid of parentheses

10x-2x-(-3(-4x+15))+19=0



We calculate terms in parentheses: -(-3(-4x+15)), so:

-3(-4x+15)

We multiply parentheses

12x-45

Back to the equation:

-(12x-45)



We add all the numbers together, and all the variables

8x-(12x-45)+19=0

We get rid of parentheses

8x-12x+45+19=0

We add all the numbers together, and all the variables

-4x+64=0

We move all terms containing x to the left, all other terms to the right

-4x=-64

x=-64/-4

x=+16

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