10x-(3x-4)=4(x-1)+9

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Solution for 10x-(3x-4)=4(x-1)+9 equation: 



10x-(3x-4)=4(x-1)+9

We move all terms to the left:

10x-(3x-4)-(4(x-1)+9)=0

We get rid of parentheses

10x-3x-(4(x-1)+9)+4=0



We calculate terms in parentheses: -(4(x-1)+9), so:

4(x-1)+9

We multiply parentheses

4x-4+9

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We add all the numbers together, and all the variables

7x-(4x+5)+4=0

We get rid of parentheses

7x-4x-5+4=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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