10x-(4x+2)=6-(21x+29)

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Solution for 10x-(4x+2)=6-(21x+29) equation: 



10x-(4x+2)=6-(21x+29)

We move all terms to the left:

10x-(4x+2)-(6-(21x+29))=0

We get rid of parentheses

10x-4x-(6-(21x+29))-2=0



We calculate terms in parentheses: -(6-(21x+29)), so:

6-(21x+29)

determiningTheFunctionDomain
-(21x+29)+6

We get rid of parentheses

-21x-29+6

We add all the numbers together, and all the variables

-21x-23

Back to the equation:

-(-21x-23)



We add all the numbers together, and all the variables

6x-(-21x-23)-2=0

We get rid of parentheses

6x+21x+23-2=0

We add all the numbers together, and all the variables

27x+21=0

We move all terms containing x to the left, all other terms to the right

27x=-21

x=-21/27

x=-7/9

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