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10x-10=x2+15
We move all terms to the left:
10x-10-(x2+15)=0
We add all the numbers together, and all the variables
-(+x^2+15)+10x-10=0
We get rid of parentheses
-x^2+10x-15-10=0
We add all the numbers together, and all the variables
-1x^2+10x-25=0
a = -1; b = 10; c = -25;
Δ = b2-4ac
Δ = 102-4·(-1)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-10}{-2}=+5$
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