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10x-12/5x-6=1
We move all terms to the left:
10x-12/5x-6-(1)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
10x-12/5x-7=0
We multiply all the terms by the denominator
10x*5x-7*5x-12=0
Wy multiply elements
50x^2-35x-12=0
a = 50; b = -35; c = -12;
Δ = b2-4ac
Δ = -352-4·50·(-12)
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5\sqrt{145}}{2*50}=\frac{35-5\sqrt{145}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5\sqrt{145}}{2*50}=\frac{35+5\sqrt{145}}{100} $
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