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10x-1=1/2x-3
We move all terms to the left:
10x-1-(1/2x-3)=0
Domain of the equation: 2x-3)!=0We get rid of parentheses
x∈R
10x-1/2x+3-1=0
We multiply all the terms by the denominator
10x*2x+3*2x-1*2x-1=0
Wy multiply elements
20x^2+6x-2x-1=0
We add all the numbers together, and all the variables
20x^2+4x-1=0
a = 20; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·20·(-1)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{6}}{2*20}=\frac{-4-4\sqrt{6}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{6}}{2*20}=\frac{-4+4\sqrt{6}}{40} $
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