10x-1=4x2

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Solution for 10x-1=4x2 equation:



10x-1=4x^2
We move all terms to the left:
10x-1-(4x^2)=0
determiningTheFunctionDomain -4x^2+10x-1=0
a = -4; b = 10; c = -1;
Δ = b2-4ac
Δ = 102-4·(-4)·(-1)
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{21}}{2*-4}=\frac{-10-2\sqrt{21}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{21}}{2*-4}=\frac{-10+2\sqrt{21}}{-8} $

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