10x-2(1x+4)=8(1x-2)+6

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Solution for 10x-2(1x+4)=8(1x-2)+6 equation:


Simplifying
10x + -2(1x + 4) = 8(1x + -2) + 6

Reorder the terms:
10x + -2(4 + 1x) = 8(1x + -2) + 6
10x + (4 * -2 + 1x * -2) = 8(1x + -2) + 6
10x + (-8 + -2x) = 8(1x + -2) + 6

Reorder the terms:
-8 + 10x + -2x = 8(1x + -2) + 6

Combine like terms: 10x + -2x = 8x
-8 + 8x = 8(1x + -2) + 6

Reorder the terms:
-8 + 8x = 8(-2 + 1x) + 6
-8 + 8x = (-2 * 8 + 1x * 8) + 6
-8 + 8x = (-16 + 8x) + 6

Reorder the terms:
-8 + 8x = -16 + 6 + 8x

Combine like terms: -16 + 6 = -10
-8 + 8x = -10 + 8x

Add '-8x' to each side of the equation.
-8 + 8x + -8x = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
-8 + 0 = -10 + 8x + -8x
-8 = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
-8 = -10 + 0
-8 = -10

Solving
-8 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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