10x-2(3+4x)=7-(x-2)

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Solution for 10x-2(3+4x)=7-(x-2) equation: 



10x-2(3+4x)=7-(x-2)

We move all terms to the left:

10x-2(3+4x)-(7-(x-2))=0

We add all the numbers together, and all the variables

10x-2(4x+3)-(7-(x-2))=0

We multiply parentheses

10x-8x-(7-(x-2))-6=0



We calculate terms in parentheses: -(7-(x-2)), so:

7-(x-2)

determiningTheFunctionDomain
-(x-2)+7

We get rid of parentheses

-x+2+7

We add all the numbers together, and all the variables

-1x+9

Back to the equation:

-(-1x+9)



We add all the numbers together, and all the variables

2x-(-1x+9)-6=0

We get rid of parentheses

2x+1x-9-6=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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