10x-2(3x-5)=3x+12

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Solution for 10x-2(3x-5)=3x+12 equation: 



10x-2(3x-5)=3x+12

We move all terms to the left:

10x-2(3x-5)-(3x+12)=0

We multiply parentheses

10x-6x-(3x+12)+10=0

We get rid of parentheses

10x-6x-3x-12+10=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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