10x-2(8x+5)+(x-5)+2(x+5)-6=

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Solution for 10x-2(8x+5)+(x-5)+2(x+5)-6= equation:


10x-2(8x+5)+(x-5)+2(x+5)-6=0

We simplify the equation to the form, which is simple to understand 
10x-2(8x+5)+(x-5)+2(x+5)-6=0

Reorder the terms in parentheses
10x+(-16x-10)+(x-5)+2*(x+5)-6=0

Remove unnecessary parentheses
+10x-16x-10+(+x-5+)+2+*(+x+5+)-6=0

Remove unnecessary parentheses
+10x-16x-10+x-5+2+*(+x+5+)-6=0

Reorder the terms in parentheses
10x-16x-10x-5+(+2x+10)-6=0

Remove unnecessary parentheses
+10x-16x-10+x-5+2x+10-6=0

We move all terms containing x to the left and all other terms to the right. 
+10x-16x+1x+2x=0+10+5-10+6

We simplify left and right side of the equation. 
-3x=+11

We divide both sides of the equation by -3 to get x. 
x=-3.66666666667

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