10x-2(x+1)=-3(1-2x)

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Solution for 10x-2(x+1)=-3(1-2x) equation: 



10x-2(x+1)=-3(1-2x)

We move all terms to the left:

10x-2(x+1)-(-3(1-2x))=0

We add all the numbers together, and all the variables

10x-2(x+1)-(-3(-2x+1))=0

We multiply parentheses

10x-2x-(-3(-2x+1))-2=0



We calculate terms in parentheses: -(-3(-2x+1)), so:

-3(-2x+1)

We multiply parentheses

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

8x-(6x-3)-2=0

We get rid of parentheses

8x-6x+3-2=0

We add all the numbers together, and all the variables

2x+1=0

We move all terms containing x to the left, all other terms to the right

2x=-1

x=-1/2

x=-1/2

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