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10x-2(x+1)=-3(1-2x)
We move all terms to the left:
10x-2(x+1)-(-3(1-2x))=0
We add all the numbers together, and all the variables
10x-2(x+1)-(-3(-2x+1))=0
We multiply parentheses
10x-2x-(-3(-2x+1))-2=0
We calculate terms in parentheses: -(-3(-2x+1)), so:We add all the numbers together, and all the variables
-3(-2x+1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
8x-(6x-3)-2=0
We get rid of parentheses
8x-6x+3-2=0
We add all the numbers together, and all the variables
2x+1=0
We move all terms containing x to the left, all other terms to the right
2x=-1
x=-1/2
x=-1/2
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