10x-2(x+3)=21

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Solution for 10x-2(x+3)=21 equation: 



10x-2(x+3)=21

We move all terms to the left:

10x-2(x+3)-(21)=0

We multiply parentheses

10x-2x-6-21=0

We add all the numbers together, and all the variables

8x-27=0

We move all terms containing x to the left, all other terms to the right

8x=27

x=27/8

x=3+3/8

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