10x-2(x+4)=8(x-2)+8

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Solution for 10x-2(x+4)=8(x-2)+8 equation:


Simplifying
10x + -2(x + 4) = 8(x + -2) + 8

Reorder the terms:
10x + -2(4 + x) = 8(x + -2) + 8
10x + (4 * -2 + x * -2) = 8(x + -2) + 8
10x + (-8 + -2x) = 8(x + -2) + 8

Reorder the terms:
-8 + 10x + -2x = 8(x + -2) + 8

Combine like terms: 10x + -2x = 8x
-8 + 8x = 8(x + -2) + 8

Reorder the terms:
-8 + 8x = 8(-2 + x) + 8
-8 + 8x = (-2 * 8 + x * 8) + 8
-8 + 8x = (-16 + 8x) + 8

Reorder the terms:
-8 + 8x = -16 + 8 + 8x

Combine like terms: -16 + 8 = -8
-8 + 8x = -8 + 8x

Add '8' to each side of the equation.
-8 + 8 + 8x = -8 + 8 + 8x

Combine like terms: -8 + 8 = 0
0 + 8x = -8 + 8 + 8x
8x = -8 + 8 + 8x

Combine like terms: -8 + 8 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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