10x-2(x-3)=8(x+1)+5

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Solution for 10x-2(x-3)=8(x+1)+5 equation:


Simplifying
10x + -2(x + -3) = 8(x + 1) + 5

Reorder the terms:
10x + -2(-3 + x) = 8(x + 1) + 5
10x + (-3 * -2 + x * -2) = 8(x + 1) + 5
10x + (6 + -2x) = 8(x + 1) + 5

Reorder the terms:
6 + 10x + -2x = 8(x + 1) + 5

Combine like terms: 10x + -2x = 8x
6 + 8x = 8(x + 1) + 5

Reorder the terms:
6 + 8x = 8(1 + x) + 5
6 + 8x = (1 * 8 + x * 8) + 5
6 + 8x = (8 + 8x) + 5

Reorder the terms:
6 + 8x = 8 + 5 + 8x

Combine like terms: 8 + 5 = 13
6 + 8x = 13 + 8x

Add '-8x' to each side of the equation.
6 + 8x + -8x = 13 + 8x + -8x

Combine like terms: 8x + -8x = 0
6 + 0 = 13 + 8x + -8x
6 = 13 + 8x + -8x

Combine like terms: 8x + -8x = 0
6 = 13 + 0
6 = 13

Solving
6 = 13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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