10x-2(x-5)=8(x+1)+4

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Solution for 10x-2(x-5)=8(x+1)+4 equation: 



10x-2(x-5)=8(x+1)+4

We move all terms to the left:

10x-2(x-5)-(8(x+1)+4)=0

We multiply parentheses

10x-2x-(8(x+1)+4)+10=0



We calculate terms in parentheses: -(8(x+1)+4), so:

8(x+1)+4

We multiply parentheses

8x+8+4

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

8x-(8x+12)+10=0

We get rid of parentheses

8x-8x-12+10=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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