10x-2(x-5)=8(x+1)+8

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Solution for 10x-2(x-5)=8(x+1)+8 equation: 



10x-2(x-5)=8(x+1)+8

We move all terms to the left:

10x-2(x-5)-(8(x+1)+8)=0

We multiply parentheses

10x-2x-(8(x+1)+8)+10=0



We calculate terms in parentheses: -(8(x+1)+8), so:

8(x+1)+8

We multiply parentheses

8x+8+8

We add all the numbers together, and all the variables

8x+16

Back to the equation:

-(8x+16)



We add all the numbers together, and all the variables

8x-(8x+16)+10=0

We get rid of parentheses

8x-8x-16+10=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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