10x-2(x-8)=8(x-1)-5

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Solution for 10x-2(x-8)=8(x-1)-5 equation:


Simplifying
10x + -2(x + -8) = 8(x + -1) + -5

Reorder the terms:
10x + -2(-8 + x) = 8(x + -1) + -5
10x + (-8 * -2 + x * -2) = 8(x + -1) + -5
10x + (16 + -2x) = 8(x + -1) + -5

Reorder the terms:
16 + 10x + -2x = 8(x + -1) + -5

Combine like terms: 10x + -2x = 8x
16 + 8x = 8(x + -1) + -5

Reorder the terms:
16 + 8x = 8(-1 + x) + -5
16 + 8x = (-1 * 8 + x * 8) + -5
16 + 8x = (-8 + 8x) + -5

Reorder the terms:
16 + 8x = -8 + -5 + 8x

Combine like terms: -8 + -5 = -13
16 + 8x = -13 + 8x

Add '-8x' to each side of the equation.
16 + 8x + -8x = -13 + 8x + -8x

Combine like terms: 8x + -8x = 0
16 + 0 = -13 + 8x + -8x
16 = -13 + 8x + -8x

Combine like terms: 8x + -8x = 0
16 = -13 + 0
16 = -13

Solving
16 = -13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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