10x-2*(3-4x)=6-(1-x)

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Solution for 10x-2*(3-4x)=6-(1-x) equation: 



10x-2(3-4x)=6-(1-x)

We move all terms to the left:

10x-2(3-4x)-(6-(1-x))=0

We add all the numbers together, and all the variables

10x-2(-4x+3)-(6-(-1x+1))=0

We multiply parentheses

10x+8x-(6-(-1x+1))-6=0



We calculate terms in parentheses: -(6-(-1x+1)), so:

6-(-1x+1)

determiningTheFunctionDomain
-(-1x+1)+6

We get rid of parentheses

1x-1+6

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

18x-(x+5)-6=0

We get rid of parentheses

18x-x-5-6=0

We add all the numbers together, and all the variables

17x-11=0

We move all terms containing x to the left, all other terms to the right

17x=11

x=11/17

x=11/17

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