10x-2+3(x-1)=2(x-1)+5(5+x)

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Solution for 10x-2+3(x-1)=2(x-1)+5(5+x) equation: 



10x-2+3(x-1)=2(x-1)+5(5+x)

We move all terms to the left:

10x-2+3(x-1)-(2(x-1)+5(5+x))=0

We add all the numbers together, and all the variables

10x+3(x-1)-(2(x-1)+5(x+5))-2=0

We multiply parentheses

10x+3x-(2(x-1)+5(x+5))-3-2=0



We calculate terms in parentheses: -(2(x-1)+5(x+5)), so:

2(x-1)+5(x+5)

We multiply parentheses

2x+5x-2+25

We add all the numbers together, and all the variables

7x+23

Back to the equation:

-(7x+23)



We add all the numbers together, and all the variables

13x-(7x+23)-5=0

We get rid of parentheses

13x-7x-23-5=0

We add all the numbers together, and all the variables

6x-28=0

We move all terms containing x to the left, all other terms to the right

6x=28

x=28/6

x=4+2/3

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