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10x-23/10x=10x/10x
We move all terms to the left:
10x-23/10x-(10x/10x)=0
Domain of the equation: 10x!=0
x!=0/10
x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10x-23/10x-(+10x/10x)=0
We get rid of parentheses
10x-23/10x-10x/10x=0
Fractions to decimals
-23/10x+10x+1=0
We multiply all the terms by the denominator
10x*10x+1*10x-23=0
Wy multiply elements
100x^2+10x-23=0
a = 100; b = 10; c = -23;
Δ = b2-4ac
Δ = 102-4·100·(-23)
Δ = 9300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9300}=\sqrt{100*93}=\sqrt{100}*\sqrt{93}=10\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{93}}{2*100}=\frac{-10-10\sqrt{93}}{200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{93}}{2*100}=\frac{-10+10\sqrt{93}}{200} $
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