10x-2x+58=10x+40

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Solution for 10x-2x+58=10x+40 equation:



10x-2x+58=10x+40
We move all terms to the left:
10x-2x+58-(10x+40)=0
We add all the numbers together, and all the variables
8x-(10x+40)+58=0
We get rid of parentheses
8x-10x-40+58=0
We add all the numbers together, and all the variables
-2x+18=0
We move all terms containing x to the left, all other terms to the right
-2x=-18
x=-18/-2
x=+9

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