10x-2x+58=10x+40

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Solution for 10x-2x+58=10x+40 equation: 



10x-2x+58=10x+40

We move all terms to the left:

10x-2x+58-(10x+40)=0

We add all the numbers together, and all the variables

8x-(10x+40)+58=0

We get rid of parentheses

8x-10x-40+58=0

We add all the numbers together, and all the variables

-2x+18=0

We move all terms containing x to the left, all other terms to the right

-2x=-18

x=-18/-2

x=+9

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