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10x-3(2x-5)=(3x+1)-6x
We move all terms to the left:
10x-3(2x-5)-((3x+1)-6x)=0
We multiply parentheses
10x-6x-((3x+1)-6x)+15=0
We calculate terms in parentheses: -((3x+1)-6x), so:We add all the numbers together, and all the variables
(3x+1)-6x
We add all the numbers together, and all the variables
-6x+(3x+1)
We get rid of parentheses
-6x+3x+1
We add all the numbers together, and all the variables
-3x+1
Back to the equation:
-(-3x+1)
4x-(-3x+1)+15=0
We get rid of parentheses
4x+3x-1+15=0
We add all the numbers together, and all the variables
7x+14=0
We move all terms containing x to the left, all other terms to the right
7x=-14
x=-14/7
x=-2
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