10x-3(4x+5)=40-(9x+6)

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Solution for 10x-3(4x+5)=40-(9x+6) equation: 



10x-3(4x+5)=40-(9x+6)

We move all terms to the left:

10x-3(4x+5)-(40-(9x+6))=0

We multiply parentheses

10x-12x-(40-(9x+6))-15=0



We calculate terms in parentheses: -(40-(9x+6)), so:

40-(9x+6)

determiningTheFunctionDomain
-(9x+6)+40

We get rid of parentheses

-9x-6+40

We add all the numbers together, and all the variables

-9x+34

Back to the equation:

-(-9x+34)



We add all the numbers together, and all the variables

-2x-(-9x+34)-15=0

We get rid of parentheses

-2x+9x-34-15=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7

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