10x-3(x-2)=8(x+1)+4

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Solution for 10x-3(x-2)=8(x+1)+4 equation: 



10x-3(x-2)=8(x+1)+4

We move all terms to the left:

10x-3(x-2)-(8(x+1)+4)=0

We multiply parentheses

10x-3x-(8(x+1)+4)+6=0



We calculate terms in parentheses: -(8(x+1)+4), so:

8(x+1)+4

We multiply parentheses

8x+8+4

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

7x-(8x+12)+6=0

We get rid of parentheses

7x-8x-12+6=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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