10x-3+147=21x-5

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Solution for 10x-3+147=21x-5 equation: 



10x-3+147=21x-5

We move all terms to the left:

10x-3+147-(21x-5)=0

We add all the numbers together, and all the variables

10x-(21x-5)+144=0

We get rid of parentheses

10x-21x+5+144=0

We add all the numbers together, and all the variables

-11x+149=0

We move all terms containing x to the left, all other terms to the right

-11x=-149

x=-149/-11

x=13+6/11

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