10x-4(x-2)=12x+7(x+1)

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Solution for 10x-4(x-2)=12x+7(x+1) equation: 



10x-4(x-2)=12x+7(x+1)

We move all terms to the left:

10x-4(x-2)-(12x+7(x+1))=0

We multiply parentheses

10x-4x-(12x+7(x+1))+8=0



We calculate terms in parentheses: -(12x+7(x+1)), so:

12x+7(x+1)

We multiply parentheses

12x+7x+7

We add all the numbers together, and all the variables

19x+7

Back to the equation:

-(19x+7)



We add all the numbers together, and all the variables

6x-(19x+7)+8=0

We get rid of parentheses

6x-19x-7+8=0

We add all the numbers together, and all the variables

-13x+1=0

We move all terms containing x to the left, all other terms to the right

-13x=-1

x=-1/-13

x=1/13

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