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10x-4(x-3)=8(2x-6)
We move all terms to the left:
10x-4(x-3)-(8(2x-6))=0
We multiply parentheses
10x-4x-(8(2x-6))+12=0
We calculate terms in parentheses: -(8(2x-6)), so:We add all the numbers together, and all the variables
8(2x-6)
We multiply parentheses
16x-48
Back to the equation:
-(16x-48)
6x-(16x-48)+12=0
We get rid of parentheses
6x-16x+48+12=0
We add all the numbers together, and all the variables
-10x+60=0
We move all terms containing x to the left, all other terms to the right
-10x=-60
x=-60/-10
x=+6
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