10x-41=(5x-7)+(2x+2)

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Solution for 10x-41=(5x-7)+(2x+2) equation: 



10x-41=(5x-7)+(2x+2)

We move all terms to the left:

10x-41-((5x-7)+(2x+2))=0



We calculate terms in parentheses: -((5x-7)+(2x+2)), so:

(5x-7)+(2x+2)

We get rid of parentheses

5x+2x-7+2

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We get rid of parentheses

10x-7x+5-41=0

We add all the numbers together, and all the variables

3x-36=0

We move all terms containing x to the left, all other terms to the right

3x=36

x=36/3

x=12

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