10x-4x+132=10x+80

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Solution for 10x-4x+132=10x+80 equation: 



10x-4x+132=10x+80

We move all terms to the left:

10x-4x+132-(10x+80)=0

We add all the numbers together, and all the variables

6x-(10x+80)+132=0

We get rid of parentheses

6x-10x-80+132=0

We add all the numbers together, and all the variables

-4x+52=0

We move all terms containing x to the left, all other terms to the right

-4x=-52

x=-52/-4

x=+13

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