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10x-5(2+x)=3(2x-4)-20
We move all terms to the left:
10x-5(2+x)-(3(2x-4)-20)=0
We add all the numbers together, and all the variables
10x-5(x+2)-(3(2x-4)-20)=0
We multiply parentheses
10x-5x-(3(2x-4)-20)-10=0
We calculate terms in parentheses: -(3(2x-4)-20), so:We add all the numbers together, and all the variables
3(2x-4)-20
We multiply parentheses
6x-12-20
We add all the numbers together, and all the variables
6x-32
Back to the equation:
-(6x-32)
5x-(6x-32)-10=0
We get rid of parentheses
5x-6x+32-10=0
We add all the numbers together, and all the variables
-1x+22=0
We move all terms containing x to the left, all other terms to the right
-x=-22
x=-22/-1
x=+22
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