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10x-54=34/6x
We move all terms to the left:
10x-54-(34/6x)=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10x-(+34/6x)-54=0
We get rid of parentheses
10x-34/6x-54=0
We multiply all the terms by the denominator
10x*6x-54*6x-34=0
Wy multiply elements
60x^2-324x-34=0
a = 60; b = -324; c = -34;
Δ = b2-4ac
Δ = -3242-4·60·(-34)
Δ = 113136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{113136}=\sqrt{16*7071}=\sqrt{16}*\sqrt{7071}=4\sqrt{7071}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-324)-4\sqrt{7071}}{2*60}=\frac{324-4\sqrt{7071}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-324)+4\sqrt{7071}}{2*60}=\frac{324+4\sqrt{7071}}{120} $
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