10x-5x=3(x-4)-2(2x+7)

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Solution for 10x-5x=3(x-4)-2(2x+7) equation: 



10x-5x=3(x-4)-2(2x+7)

We move all terms to the left:

10x-5x-(3(x-4)-2(2x+7))=0

We add all the numbers together, and all the variables

5x-(3(x-4)-2(2x+7))=0



We calculate terms in parentheses: -(3(x-4)-2(2x+7)), so:

3(x-4)-2(2x+7)

We multiply parentheses

3x-4x-12-14

We add all the numbers together, and all the variables

-1x-26

Back to the equation:

-(-1x-26)



We get rid of parentheses

5x+1x+26=0

We add all the numbers together, and all the variables

6x+26=0

We move all terms containing x to the left, all other terms to the right

6x=-26

x=-26/6

x=-4+1/3

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