10x-8+4x=2(10x-4)

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Solution for 10x-8+4x=2(10x-4) equation:



10x-8+4x=2(10x-4)
We move all terms to the left:
10x-8+4x-(2(10x-4))=0
We add all the numbers together, and all the variables
14x-(2(10x-4))-8=0
We calculate terms in parentheses: -(2(10x-4)), so:
2(10x-4)
We multiply parentheses
20x-8
Back to the equation:
-(20x-8)
We get rid of parentheses
14x-20x+8-8=0
We add all the numbers together, and all the variables
-6x=0
x=0/-6
x=0

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