10x-8+4x=2(10x-4)

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Solution for 10x-8+4x=2(10x-4) equation: 



10x-8+4x=2(10x-4)

We move all terms to the left:

10x-8+4x-(2(10x-4))=0

We add all the numbers together, and all the variables

14x-(2(10x-4))-8=0



We calculate terms in parentheses: -(2(10x-4)), so:

2(10x-4)

We multiply parentheses

20x-8

Back to the equation:

-(20x-8)



We get rid of parentheses

14x-20x+8-8=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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