10x-8x-3/4=2(x-3)

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Solution for 10x-8x-3/4=2(x-3) equation: 


x in (-oo:+oo)

10*x-(8*x)-(3/4) = 2*(x-3) // - 2*(x-3)

10*x-(2*(x-3))-(8*x)-(3/4) = 0

10*x-2*(x-3)-8*x-3/4 = 0

(-2*4*(x-3))/4+(4*10*x)/4+(-8*4*x)/4-3/4 = 0

4*10*x-2*4*(x-3)-8*4*x-3 = 0

32*x-32*x-3+24 = 0

24-3 = 0

21 = 0

21/4 = 0

21/4 = 0 // * 4

21 = 0

21 = 0

x belongs to the empty set

x belongs to the empty set

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