If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2+100x+210=0
a = 10; b = 100; c = +210;
Δ = b2-4ac
Δ = 1002-4·10·210
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-40}{2*10}=\frac{-140}{20} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+40}{2*10}=\frac{-60}{20} =-3 $
| 10-4(x+2)=-14 | | 4x2−7x+3=0 | | q−54=10 | | 4(p+5)=2p-12 | | 45+i=92 | | -3(x-2)=-2x+1+4x | | 72+40+4x+12=180 | | (40)+(6x)+(3x+5)=180 | | u+12=98 | | s10=4 | | 4x+10=×+40 | | 16=n/4+21 | | 93+x+1=3x | | 10−3/n=6 | | (7x+3)+(6x+6)+(67)=180 | | 10−n/3=6 | | F(t)=(t+4)(t-2.3) | | 7x+2x-4=-8+3(3x-2) | | 10=g-28 | | (x+5)2=27 | | 63=u+45 | | −8−n/2=−13 | | -10x-9=-17+x | | 18=6+n/3 | | (2x-11)+(2x+1)+(90)=180 | | A^-6a=0 | | 3x=(x-9)+2x | | 8=88÷f | | 2x^2-x=12-3x | | 8x-18=38* | | 8y+34=6(y+5) | | 2x-x=12-3x |