10x2+105x-580=0

Solution for 10x2+105x-580=0 equation:

10x^2+105x-580=0

a = 10; b = 105; c = -580;
Δ = b2-4ac
Δ = 1052-4·10·(-580)
Δ = 34225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34225}=185$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-185}{2*10}=\frac{-290}{20}
=-14+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+185}{2*10}=\frac{80}{20}
=4
$