10x2+12=52

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Solution for 10x2+12=52 equation:



10x^2+12=52
We move all terms to the left:
10x^2+12-(52)=0
We add all the numbers together, and all the variables
10x^2-40=0
a = 10; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·10·(-40)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*10}=\frac{-40}{20} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*10}=\frac{40}{20} =2 $

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