10x2+12x-11=0

Solution for 10x2+12x-11=0 equation:

10x^2+12x-11=0

a = 10; b = 12; c = -11;
Δ = b2-4ac
Δ = 122-4·10·(-11)
Δ = 584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{584}=\sqrt{4*146}=\sqrt{4}*\sqrt{146}=2\sqrt{146}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{146}}{2*10}=\frac{-12-2\sqrt{146}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{146}}{2*10}=\frac{-12+2\sqrt{146}}{20}
$