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10x^2+20x+10=0
a = 10; b = 20; c = +10;
Δ = b2-4ac
Δ = 202-4·10·10
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-20}{20}=-1$
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